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NEET Chemistry: Coordination Compounds Practice Questions

7 free multiple-choice questions on Coordination Compounds for NEET Chemistry, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.

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  1. Q1. In an octahedral complex, if the d-orbitals are split by the presence of ligands, what is the resulting geometry of the complex if there are no experimental distortions?

    • AOctahedral
    • BSquare Planar
    • CTetrahedral
    • DTrigonal Pyramidal
    Show answer & explanation

    Correct answer: A — Octahedral

    For an octahedral geometry, the d-orbitals are split into t₍2g) and e_g sets. The geometry itself remains octahedral.

  2. Q2. The term 'denticity' in the context of coordination compounds refers to the number of:

    • Avalence electrons in the metal
    • Belectrons in the d-orbitals
    • Cdonor atoms within a single ligand
    • Ddonor atoms within a single ligand and bonding sites
    Show answer & explanation

    Correct answer: D — donor atoms within a single ligand and bonding sites

    Denticity is the property of a ligand to bond to the central metal ion. It defines how many donor atoms (or bonding sites) the ligand uses to coordinate to the metal.

  3. Q3. When a metal ion forms a complex with ligands, the relative energy separation between the split d-orbitals is determined by the strength of the interaction between the metal and the ligand. Stronger ligands lead to:

    • Aincreased spin multiplicity
    • Bno splitting
    • Clarger crystal field splitting
    • Dsmaller crystal field splitting
    Show answer & explanation

    Correct answer: C — larger crystal field splitting

    The magnitude of the crystal field splitting energy (Δ) is directly proportional to the strength of the ligand field, which is dictated by the bonding characteristics.

  4. Q4. In a complex exhibiting a high spin configuration, what is the arrangement of electrons in the split d-orbitals (assuming octahedral geometry)?

    • AMaximum pairing occurs in the lower energy set
    • BAll electrons occupy the higher energy set
    • CAll electrons paired
    • DMaximum number of unpaired electrons
    Show answer & explanation

    Correct answer: D — Maximum number of unpaired electrons

    High spin complexes maximize the number of unpaired electrons by minimizing the pairing energy, meaning electrons occupy the higher energy orbitals singly before pairing up.

  5. Q5. A coordination sphere consists of the central metal ion and all the ligands directly bonded to it. This sphere is defined by:

    • AThe outer coordination shell
    • BThe secondary coordination sphere
    • CThe bridging structure
    • DThe primary coordination sphere
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    Correct answer: D — The primary coordination sphere

    The coordination sphere refers to the immediate environment of the central metal ion, which includes all the ligands directly attached to it.

  6. Q6. Consider the complex Ni(H₂O)₆²⁺. If H₂O acts as a weak field ligand, the complex is expected to be in which spin state?

    • AIntermediate spin
    • BDiamagnetic
    • CHigh spin
    • DLow spin
    Show answer & explanation

    Correct answer: C — High spin

    For Ni²⁺ (d8 system) with weak field ligands, the pairing energy is relatively high, favoring the maximum number of unpaired electrons, leading to the high spin state.

  7. Q7. When naming coordination compounds, the prefix used to denote the coordination number is:

    • ACoordination
    • BValency
    • CLigand
    • DOxidation
    Show answer & explanation

    Correct answer: A — Coordination

    The coordination number is indicated by the prefix 'co' (or the use of Roman numerals in IUPAC naming) which specifies the number of ligands coordinated to the metal center.

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