NEET Chemistry: de Broglie's relationship Practice Questions
14 free multiple-choice questions on de Broglie's relationship (Atomic Structure) for NEET Chemistry, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. Which of the following statements accurately describes the nature of the de Broglie wavelength?
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Correct answer: B — It is the wavelength associated with the particle's momentum.
The de Broglie wavelength is fundamentally the wavelength associated with the particle's momentum (p), linking its particle properties to its wave properties.
Q2. The de Broglie hypothesis states that every particle exhibits wave-like properties. This relationship fundamentally links the particle's momentum to its wavelength. What constant is central to this relationship?
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Correct answer: B — Planck's constant (h)
De Broglie's relationship, which connects the momentum (p) of a particle to its wavelength (λ), is fundamentally defined by Planck's constant (h). The relationship is p = h/λ.
Q3. The de Broglie hypothesis suggests that matter can exhibit wave characteristics. If the momentum of a particle is constant, what must be true about its de Broglie wavelength?
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Correct answer: D — The wavelength is inversely proportional to momentum
Since λ= h/p, if the momentum (p) is constant, the wavelength (λ) must also be constant, meaning it is independent of momentum in this scenario (in the context of the fundamental equation).
Q4. If a particle has a specific momentum, the corresponding de Broglie wavelength is inversely proportional to the momentum. This means that for a fixed value of Planck's constant (h), what happens to the wavelength (λ) if the momentum (p) of the particle is doubled?
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Correct answer: B — The wavelength is doubled
Since λ= h/p, the wavelength is inversely proportional to the momentum. If momentum (p) is doubled, the wavelength (λ) must be halved (h/(2p) = λ/2).
Q5. What is the fundamental physical constant involved in de Broglie's relationship between wavelength and momentum?
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Correct answer: D — Planck's constant (h)
The de Broglie relationship is λ= h/p. Planck's constant (h) is the constant that links the wave nature of matter (wavelength) to its particle nature (momentum).
Q6. The wave nature of matter is described by the fact that particles exhibit wave-like properties. This concept is fundamentally linked to the relationship between energy and wavelength, as established by de Broglie. Which physical quantity is related to the particle's kinetic energy?
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Correct answer: B — Wavelength
The relationship involves energy (E) and wavelength (λ= h/p = h/mv). Kinetic energy (E = 1/2 mv²) is directly related to the momentum and thus the wavelength.
Q7. The concept of de Broglie's relationship fundamentally establishes which concept in quantum mechanics?
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Correct answer: C — Wave-particle duality
De Broglie's hypothesis introduces the concept of wave-particle duality, stating that matter exhibits both wave-like and particle-like properties.
Q8. Which of the following quantities is directly related to the wavelength associated with a particle according to the de Broglie hypothesis?
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Correct answer: D — Momentum
The de Broglie wavelength is directly determined by the particle's momentum (λ= h/p). Therefore, momentum is the direct physical quantity linked to the wavelength.
Q9. For a particle with a given momentum p, the de Broglie wavelength (λ) is inversely proportional to which physical constant?
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Correct answer: B — Planck's constant
The relationship is λ= h/p. Since h is constant, the wavelength (λ) is inversely proportional to the momentum (p).
Q10. A particle has a momentum p. According to de Broglie's hypothesis, what is the corresponding wavelength associated with this particle?
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Correct answer: D — λ= h/p
De Broglie's relationship states that the momentum (p) of a particle is inversely proportional to its wavelength (λ), given by the formula p = h/λ. Rearranging this formula gives λ= h/p.
Q11. The de Broglie wavelength (λ) associated with a particle is directly proportional to which physical quantity?
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Correct answer: A — Momentum of the particle
De Broglie wavelength is given by λ= h/p, where h is Planck's constant and p is momentum. Therefore, λ is inversely proportional to momentum, but directly proportional to h. In the context of the choices, the relationship is directly tied to momentum (p).
Q12. According to de Broglie's hypothesis, the relationship between the momentum (p) and the de Broglie wavelength (λ) of a particle is given by:
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Correct answer: B — p = h/λ
De Broglie's relationship states that the momentum (p) of a particle is inversely proportional to its de Broglie wavelength (λ). The correct mathematical form is p = h/λ, where h is Planck's constant.
Q13. For an electron at rest, its de Broglie wavelength is related to its mass and Planck's constant. This relationship highlights the wave nature of which fundamental particle?
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Correct answer: B — Electron
The de Broglie relationship applies to all matter. The electron is a fundamental particle whose wave nature is described by its associated wavelength determined by its momentum and Planck's constant.
Q14. Planck's constant (h) has the unit of which physical quantity in SI units?
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Correct answer: B — Joule-second
Planck's constant (h) has the SI unit of Joule-second (J·s). This constant links the energy of a photon to its frequency and the momentum of a particle to its wavelength.
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