NEET Physics: oscillations of a spring restoring force and force constant Practice Questions
14 free multiple-choice questions on oscillations of a spring restoring force and force constant (Oscillations and Waves) for NEET Physics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. A spring obeys Hooke's law. If the extension of the spring is doubled, what happens to the restoring force exerted by the spring?
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Correct answer: A — The restoring force is doubled
According to Hooke's law, the restoring force (F) is directly proportional to the extension (x), i.e., F = kx. If the extension is doubled, the force exerted by the spring is also doubled.
Q2. If the amplitude of oscillation of a mass attached to a spring is increased, how does the period of oscillation change?
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Correct answer: C — It remains unchanged
The period of oscillation for a mass-spring system is given by T = 2π√(m/k). Since the period depends only on the mass (m) and the force constant (k), changing the amplitude does not affect the period.
Q3. The constant 'k' in Hooke's Law (F = -kx) represents which physical property of the spring?
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Correct answer: B — Force constant or spring constant
The constant 'k' is known as the force constant or spring constant, which measures the stiffness of the spring.
Q4. What is the SI unit of the force constant (k)?
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Correct answer: C — Newton per meter (N/m)
Since Force (F) is in Newtons (N) and displacement (x) is in meters (m), the unit for the force constant k = F/x is N/m.
Q5. If the force constant (k) of a spring is doubled while the displacement remains the same, what happens to the restoring force exerted by the spring?
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Correct answer: A — It is doubled
Since F = kx, if k is doubled and x is constant, the restoring force F will also be doubled.
Q6. If the displacement of a spring is reduced to half its original value, how does the elastic potential energy stored in it change?
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Correct answer: B — It is reduced to one-fourth
Since potential energy U ∝ x², if the displacement (x) is halved, the new energy will be proportional to (x/2)² = x²/4. Therefore, the potential energy is reduced to one-fourth of the original value.
Q7. If a spring is stretched by a distance x, and a force F is applied, what is the relationship between the applied force and the spring constant k?
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Correct answer: D — F = kx
According to Hooke's Law, the force F exerted by the spring is directly proportional to the extension x, meaning F = kx.
Q8. Which physical quantity determines the stiffness of a spring?
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Correct answer: D — The force constant
The stiffness or elastic constant of a spring is defined by the force constant (k), which relates the restoring force to the displacement (F = kx).
Q9. A spring obeys Hooke's law. If a force F is applied to stretch the spring by a distance x, the magnitude of the restoring force exerted by the spring is proportional to:
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Correct answer: A — x
According to Hooke's law, the magnitude of the restoring force exerted by the spring is directly proportional to the extension x. Thus, F ∝ x (or F = kx).
Q10. When a spring is displaced from its equilibrium position and allowed to oscillate, the potential energy stored in the spring is directly proportional to the square of the displacement. What is this relationship based on?
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Correct answer: B — The potential energy of the spring
The elastic potential energy (U) stored in a spring is given by the formula U = 1/2 k x², where x is the displacement and k is the spring constant. Thus, the potential energy is proportional to the square of the displacement.
Q11. The relationship between the time period of oscillation of a spring and its physical properties is governed by which constant?
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Correct answer: A — The stiffness of the spring
The time period (T) of oscillation for a spring depends on the stiffness of the spring (which is related to the force constant, k) and the mass of the oscillating body. A stiffer spring (larger effective constant) results in a shorter time period for a given oscillation.
Q12. Which quantity is directly proportional to the stiffness of a spring?
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Correct answer: A — Force constant (k)
The force constant (k) is the measure of stiffness. A larger k means the spring exerts a larger restoring force for a given displacement.
Q13. The restoring force exerted by a spring is always directed towards the equilibrium position. This implies that the force is:
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Correct answer: A — Always negative
The restoring force is proportional to the displacement (F ∝ -x). If the spring is stretched (positive x), the force is directed backward (negative direction), pulling it towards equilibrium.
Q14. What is the restoring force exerted by a spring when it is displaced from its equilibrium position?
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Correct answer: A — Proportional to the displacement
According to Hooke's Law, the restoring force (F) exerted by a spring is directly proportional to the displacement (x) from the equilibrium position (F = -kx).
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