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NEET Physics: Vector. Addition and subtraction Practice Questions

10 free multiple-choice questions on Vector. Addition and subtraction (Kinematics) for NEET Physics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.

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  1. Q1. If the resultant of two vectors is zero, A⃗ + B⃗ = 0, then the relationship between their magnitudes |A⃗| and |B⃗| is:

    • A|A⃗| = -|B⃗|
    • B|A⃗| = |B⃗|
    • C|A⃗| = 2|B⃗|
    • D|A⃗| = 0
    Show answer & explanation

    Correct answer: B — |A⃗| = |B⃗|

    If A⃗ + B⃗ = 0, then A⃗ = -B⃗. This implies that the two vectors must have equal magnitudes and be in exactly opposite directions (i.e., |A⃗| = |B⃗|).

  2. Q2. If two vectors, A⃗ and B⃗, are in the same direction, what is the magnitude of their resultant vector R⃗ = A⃗ + B⃗?

    • A√(|A⃗|² + |B⃗|²)
    • B|A⃗| - |B⃗|
    • C|A⃗| + |B⃗|
    • D|A⃗ - B⃗|
    Show answer & explanation

    Correct answer: C — |A⃗| + |B⃗|

    When two vectors are in the same direction, their resultant magnitude is the simple sum of their individual magnitudes.

  3. Q3. If two vectors of magnitude 3 and 4 act in the same direction, what is the magnitude of their resultant vector?

    • A4
    • B5
    • C7
    • D3
    Show answer & explanation

    Correct answer: B — 5

    When vectors act in the same direction, their magnitudes are added to find the resultant magnitude: 3 + 4 = 7

  4. Q4. When two vectors are in the same direction, the magnitude of their resultant is calculated by:

    • ADividing their magnitudes
    • BSubtracting their magnitudes
    • CAdding their magnitudes
    • DMultiplying their magnitudes
    Show answer & explanation

    Correct answer: C — Adding their magnitudes

    If vectors are parallel (in the same direction), their resultant magnitude is the sum of their individual magnitudes.

  5. Q5. Two vectors, P⃗ and Q⃗, have magnitudes of 5 units and 12 units respectively, and the angle between them is 90°. What is the magnitude of the difference vector |P⃗ - Q⃗|?

    • A13
    • B5
    • C10
    • D12
    Show answer & explanation

    Correct answer: A — 13

    Using the law of cosines for the difference in magnitude: |P⃗ - Q⃗|² = |P⃗|² + |Q⃗|² - 2|P⃗||Q⃗|cos(90°) = 5² + 12² - 0 = 25 + 144 = 169. Thus, |P⃗ - Q⃗| = √169 = 13.

  6. Q6. If vector A⃗ is 5 units East and vector B⃗ is 5 units North, what is the magnitude of the resultant vector R⃗ = A⃗ + B⃗?

    • AB=5 units
    • BC=7.07 units
    • CD=10 units
    • DA=5 units
    Show answer & explanation

    Correct answer: B — C=7.07 units

    Since the vectors are perpendicular, the resultant magnitude is found by R = √(5² + 5²) = √(25 + 25) = √50 ≈ 7.07 units.

  7. Q7. Two forces, 10 N acting North and 10 N acting South, are applied to an object. What is the net force acting on the object?

    • AA=20 N North
    • BC=0 N
    • CB=20 N South
    • DD=10 N
    Show answer & explanation

    Correct answer: B — C=0 N

    Since the forces are equal in magnitude and opposite in direction, their vector sum (net force) is zero. 10 N - 10 N = 0.

  8. Q8. Which of the following statements correctly describes the subtraction of two vectors, A⃗ - B⃗?

    • AIt is only defined when vectors are collinear
    • BIt is always the negative of the sum of the magnitudes
    • CIt results in the vector pointing from B to A
    • DIt is the same as A⃗ + (-B⃗)
    Show answer & explanation

    Correct answer: D — It is the same as A⃗ + (-B⃗)

    Vector subtraction A⃗ - B⃗ is mathematically equivalent to vector addition of A⃗ and the negative of B⃗, i.e., A⃗ + (-B⃗).

  9. Q9. If two vectors A and B are perpendicular to each other, what is the magnitude of their resultant vector (A + B)?

    • AC=A-B
    • BA=A+B
    • CB=A+B
    • DD=A-B
    Show answer & explanation

    Correct answer: C — B=A+B

    When two vectors are perpendicular, the magnitude of the resultant vector is found using the Pythagorean theorem: R = sqrt(A² + B²).

  10. Q10. If two vectors A⃗ and B⃗ are anti-parallel (opposite directions), then the magnitude of their difference |A⃗ - B⃗| is equal to:

    • A|A⃗| - |B⃗| cos(180°)
    • B|A⃗| - |B⃗|
    • C|A⃗| + |B⃗|
    • D|A⃗| + |B⃗| cos(180°)
    Show answer & explanation

    Correct answer: C — |A⃗| + |B⃗|

    If A⃗ and B⃗ are anti-parallel, θ= 180°. |A - B| = √|A|² + |B|² - 2|A||B|cos(180^°) = √|A|² + |B|² + 2|A||B| = √(|A| + |B|)² = |A| + |B|.

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