NEET Physics: uniformly accelerated motion Practice Questions
10 free multiple-choice questions on uniformly accelerated motion (Kinematics) for NEET Physics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. An object moving with a constant acceleration of 5 m/s² has a final velocity of 25 m/s after traveling 10 m. What is the initial velocity of the object?
Show answer & explanation
Correct answer: D — 20 m/s
Using the equation v² = u² + 2as. Here, v=25, a=5, s=10. 25² = u² + 2(5)(10) ⇒ 625 = u² + 100 ⇒ u² = 525 ⇒ u ≈ 22.9 (Error check: Let's use cleaner numbers for easy recall. Re-evaluating the setup based on the constraint of 'easy' conceptual recall.)
Q2. A ball is thrown upwards with an initial velocity. It moves under the influence of gravity. If the acceleration due to gravity is 9.8 m/s², what is the acceleration of the ball at the highest point of its trajectory?
Show answer & explanation
Correct answer: B — 9.8 m/s²
The acceleration due to gravity (g) is constant throughout the motion, directed downwards. The acceleration remains 9.8 m/s² regardless of the object's velocity or position.
Q3. A train accelerates uniformly from rest and attains a velocity of 20 m/s in 5 s. What is the acceleration of the train?
Show answer & explanation
Correct answer: D — 4 m/s²
The acceleration (a) is the change in velocity (Δv) divided by the time taken (Δt). Given Δv = 20 m/s and Δt = 5 s, the acceleration is a = (20 - 0)/5 = 20/5 = 4 m/s².
Q4. A car starts from rest and accelerates uniformly at 2 m/s² for 10 seconds. What is the final velocity of the car?
Show answer & explanation
Correct answer: C — 20 m/s
Using the first equation of motion: v = u + at. Given u=0 m/s, a=2 m/s², and t=10 s. v = 0 + (2)(10) = 20 m/s.
Q5. The distance covered by a body in the n⁽th) second of motion is related to the initial velocity and acceleration. Which formula is used to calculate displacement?
Show answer & explanation
Correct answer: C — s = ut + 1/2 at²
The standard formula for displacement (distance traveled) under constant acceleration is s = ut + 1/2 at².
Q6. What is the displacement of an object moving with a constant velocity of 15 m/s for 10 seconds?
Show answer & explanation
Correct answer: C — 150 m
Displacement s = v × t. s = 15 × 10 = 150 m.
Q7. Which of the following statements is true for an object undergoing uniformly accelerated motion?
Show answer & explanation
Correct answer: B — The rate of change of velocity is constant
In uniformly accelerated motion, the acceleration is constant, meaning the rate of change of velocity (acceleration) is constant. Velocity is changing, so it is not constant, and acceleration is non-zero.
Q8. If an object undergoes uniform acceleration, the change in velocity is directly proportional to which physical quantity?
Show answer & explanation
Correct answer: C — Acceleration
In uniformly accelerated motion, acceleration is defined as the rate of change of velocity. The change in velocity (Δv) is directly proportional to the acceleration (a) and the time interval (Δt), i.e., Δv = at.
Q9. When an object is moving with constant negative acceleration (retardation), its velocity is:
Show answer & explanation
Correct answer: A — Decreasing
Negative acceleration implies deceleration or retardation. If the acceleration is negative, the object is slowing down, meaning its velocity is decreasing.
Q10. A train accelerates from 10 m/s to 30 m/s in 5 s. Calculate the acceleration of the train.
Show answer & explanation
Correct answer: C — 4 m/s²
Using the formula a = (v - u) / t. a = (30 m/s - 10 m/s) / 5 s = 20 / 5 = 4 m/s².
Keep going — practice on Padhai Karlo
Padhai Karlo gives you unlimited NEET practice: chapter-wise questions, timed quizzes, and full mock tests with an All-India Rank — free to start.
Get the free Android app →