NEET Physics: relations for uniformly accelerated motion Practice Questions
10 free multiple-choice questions on relations for uniformly accelerated motion (Kinematics) for NEET Physics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. Two objects, A and B, start moving from the same point with the same initial velocity. If object A has a larger acceleration than object B, how will their velocities compare after the same time t?
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Correct answer: C — v_A > v_B
Since both objects start with the same initial velocity (u_A = u_B) and travel for the same time (t), the object with the larger acceleration (a_A > a_B) will have a greater final velocity (v = u + at).
Q2. The distance covered by a body in the n⁽th) second of motion under uniform acceleration is given by which relation?
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Correct answer: B — s = 1/2a(2n-1)
The distance covered in the n⁽th) second is sₙ = u + a((2n-1)/2). This simplifies to sₙ = 1/2a(2n-1).
Q3. A car starts from rest and accelerates uniformly at 2 m/s² for 10 seconds. What is its final velocity?
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Correct answer: C — 20 m/s
Using the first equation of motion, v = u + at. Here, u=0, a=2 m/s², and t=10 s. So, v = 0 + (2)(10) = 20 m/s.
Q4. Which equation of motion is used to find the displacement (s) when initial velocity (u), final velocity (v), and acceleration (a) are known?
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Correct answer: B — v² = u² + 2as
The equation v² = u² + 2as directly relates the final velocity (v), initial velocity (u), acceleration (a), and displacement (s).
Q5. If the average velocity of a body over a time interval is the arithmetic mean of its initial and final velocities, what relationship must exist between the acceleration and the time taken?
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Correct answer: D — a = (v-u)/t
The average velocity (v̄) is v̄ = (u+v)/2. Since v̄ = (u+v)/2 = (u + (u+at))/2 = u + 1/2at, rearranging gives a = (2(v̄-u))/t, which relates directly to the definition of acceleration.
Q6. A car accelerates from 10 m/s to 20 m/s in 5 seconds. What is the acceleration of the car?
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Correct answer: B — 2 m/s²
Acceleration (a) is the change in velocity divided by the time taken. a = (v - u) / t = (20 - 10) / 5 = 10 / 5 = 2 m/s²
Q7. A train accelerates from 10 m/s to 20 m/s in 5 seconds. What is the acceleration of the train?
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Correct answer: C — 2 m/s²
Using a = (v-u)/t. Here, v=20 m/s, u=10 m/s, and t=5 s. So, a = (20 - 10)/5 = 10/5 = 2 m/s².
Q8. A body starts from rest and moves with uniform acceleration. If the displacement is directly proportional to the square of time, which equation is applicable?
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Correct answer: B — s = 1/2at²
The equation s = ut + 1/2at² shows that displacement s is a function of t² (assuming u=0). Specifically, s = 1/2at².
Q9. Which equation of motion relates initial velocity (u), final velocity (v), acceleration (a), and displacement (s)?
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Correct answer: B — v² = u² + 2as
The relation v² = u² + 2as directly connects the change in velocity squared, initial velocity, acceleration, and displacement.
Q10. A car starting from rest accelerates uniformly and covers a distance of 100 m in 10 seconds. What is the acceleration of the car?
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Correct answer: B — 2 m/s²
Using the second equation of motion, s = ut + 1/2at². Given u=0, s=100 m, t=10 s. 100 = 0 + 1/2a(10)². 100 = 50a. Therefore, a = 2 m/s².
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