NEET Chemistry: Hess’s law of constant heat summation Practice Questions
12 free multiple-choice questions on Hess’s law of constant heat summation (Chemical Thermodynamics) for NEET Chemistry, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. Consider the following reactions: Reaction 1: X → Y (ΔH₁ = -20 kJ) and Reaction 2: Y → Z (ΔH₂ = +30 kJ). What is the enthalpy change for the overall reaction X → Z?
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Correct answer: A — +10 kJ
By summing the two reactions, X → Y and Y → Z, we get X → Z. ΔHₒᵥₑᵣₐₗₗ = ΔH₁ + ΔH₂ = (-20 kJ) + (+30 kJ) = +10 kJ.
Q2. Consider the reaction: C(graphite) + O₂(g) → CO₂(g). If the enthalpy change for this reaction is known, and we reverse the reaction, what is the sign of the enthalpy change of the reversed reaction?
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Correct answer: D — The sign will be opposite to the original reaction.
Reversing a reaction changes the sign of the enthalpy change. If ΔH = -X, then the reverse reaction ΔHᵣₑᵥ = -(-X) = +X.
Q3. Which of the following statements accurately describes the principle underlying Hess's Law?
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Correct answer: A — The energy of a system depends only on the initial and final states.
Hess's Law relies on the concept that the change in enthalpy depends only on the initial and final states of the system, supporting the principle of energy conservation.
Q4. If Reaction 1 is A → B with ΔH₁ = -20 kJ and Reaction 2 is B → C with ΔH₂ = +30 kJ, what is the enthalpy change for the overall reaction A → C?
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Correct answer: A — +10 kJ
Using Hess's Law, the enthalpy of the overall reaction is the sum of the individual steps: ΔHₜₒₜₐₗ = ΔH₁ + ΔH₂ = -20 kJ + 30 kJ = +10 kJ.
Q5. Hess's Law of constant heat summation is based on which fundamental thermodynamic principle?
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Correct answer: D — The First Law of Thermodynamics.
Hess's Law is a direct consequence of the First Law of Thermodynamics, which states that energy cannot be created or destroyed, only transformed.
Q6. If the enthalpy change for a specific reaction is ΔH = +100 kJ, what is the enthalpy change for the reverse reaction?
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Correct answer: C — -100 kJ
The enthalpy change of a reaction is a state function. Reversing a reaction changes the sign of the enthalpy change. Thus, if ΔH = +100 kJ, then the reverse reaction has an enthalpy change of -100 kJ.
Q7. Hess's Law is based on the principle that enthalpy change is a state function. What does this imply about the energy of a system?
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Correct answer: D — The internal energy of a system is independent of the process path.
Since enthalpy (ΔH) is a state function, the change in enthalpy between two states is independent of the specific path taken between those states. This is the fundamental basis of Hess's Law.
Q8. If reaction 1 → 2 has ΔH₁ and reaction 2 → 3 has ΔH₂, then the enthalpy change for the overall reaction 1 → 3 is given by:
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Correct answer: A — ΔH₁ + ΔH₂
According to Hess's Law, the enthalpy change for the overall reaction is the sum of the enthalpy changes of the individual steps.
Q9. The enthalpy change for the formation of 1 mole of an ideal gas from its constituent elements is always:
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Correct answer: D — Negative, as energy is released.
For the formation of an ideal gas from its constituent elements under standard conditions, the process is always exothermic (releases heat), hence ΔH is negative.
Q10. Which of the following statements is a correct expression of Hess's Law?
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Correct answer: B — The enthalpy change of a reaction depends only on the initial and final states of the system.
Hess's Law states that the total enthalpy change for a reaction is the same, regardless of the path taken between the initial and final states. This is directly related to the state function nature of enthalpy.
Q11. In applying Hess's Law of constant heat summation, if the enthalpy change for a reaction A → B is ΔH₁ and the enthalpy change for the reaction B → C is ΔH₂, what is the enthalpy change for the overall reaction A → C by combining these two reactions?
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Correct answer: D — ΔH = ΔH₁ + ΔH₂
Hess's Law states that the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps. Therefore, ΔH₍A → C) = ΔH₍A → B) + ΔH₍B → C).
Q12. If the enthalpy changes for two successive reactions are given as ΔH₁ = -10 kJ for the reaction A → B and ΔH₂ = +5 kJ for the reaction B → C, what is the enthalpy change for the overall reaction A → C?
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Correct answer: D — 15 kJ
Hess's Law states that the total enthalpy change for a reaction is the sum of the enthalpy changes of the individual steps. For the reaction A → C, we sum the changes: ΔHₜₒₜₐₗ = ΔH(A → B) + ΔH(B → C). Using the example values: ΔHₜₒₜₐₗ = (-10 kJ) + (+25 kJ) = +15 kJ.
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