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NEET Chemistry: Transition Elements properties and complex formation Practice Questions

15 free multiple-choice questions on Transition Elements properties and complex formation (d- and f-Block Elements) for NEET Chemistry, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.

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  1. Q1. Which transition metal ion typically exhibits a high degree of spin-orbit coupling, leading to strong magnetic effects?

    • ASc3+
    • BFe3+
    • CZn2+
    • DTi4+
    Show answer & explanation

    Correct answer: B — Fe3+

    Transition metals, especially those with partially filled d-orbitals (like Fe3+), exhibit strong spin-orbit coupling which influences their magnetic and spectroscopic properties.

  2. Q2. Which of the following statements is generally true regarding the bonding in transition elements?

    • AThe d-orbitals participate exclusively in sigma (σ) bonding.
    • BThe participation of d-orbitals is crucial for forming both sigma (σ) and pi (π) bonds with ligands.
    • CThe energy difference between the 3d and 4d orbitals is significant enough to prevent inter-orbital mixing.
    • DTransition metals exclusively form ionic bonds with non-metals.
    Show answer & explanation

    Correct answer: B — The participation of d-orbitals is crucial for forming both sigma (σ) and pi (π) bonds with ligands.

    Transition elements exhibit complex bonding where the d-orbitals are partially filled and participate actively in the formation of both sigma (σ) and pi (π) bonds with ligands.

  3. Q3. In the context of d-block elements, which species is generally the most stable?

    • ANickel(II) ion
    • BIron(III) ion
    • CCopper(I) ion
    • DManganese(II) ion
    Show answer & explanation

    Correct answer: D — Manganese(II) ion

    The Manganese(II) ion (Mn²⁺) is often considered the most stable configuration among the common oxidation states of transition metals, often correlating with the half-filled stability of the d-subshell.

  4. Q4. What is the primary effect of the Lanthanide contraction on the elements of the 5d series?

    • AIncreased ionic radii
    • BNo significant change
    • CIncreased electronegativity
    • DDecreased ionic radii
    Show answer & explanation

    Correct answer: A — Increased ionic radii

    The lanthanide contraction causes a steady decrease in the atomic and ionic radii of the elements as we move across the series due to poor shielding by 4f electrons.

  5. Q5. The maximum number of lone pairs that can be accommodated in a d-orbital is:

    • A4
    • B3
    • C2
    • D6
    Show answer & explanation

    Correct answer: D — 6

    The d-orbital has 5 degenerate orbitals (d₍xy), d₍xz), d₍yz), d₍x²-y²), d₍z²)), and each orbital can accommodate 2 electrons, thus providing a total of 5 × 2 = 10 electrons, which corresponds to 5 lone pairs (or 10 electrons).

  6. Q6. The general trend in the size of the lanthanide elements is:

    • ADecreases across the series
    • BFluctuates randomly
    • CIncreases across the series
    • DRemains constant
    Show answer & explanation

    Correct answer: C — Increases across the series

    Due to poor shielding effect of the inner electrons, the atomic radius increases steadily from La to Lu (Lanthanide contraction is a related effect).

  7. Q7. The magnetic behavior of a complex is determined by the number of unpaired electrons. If a complex is diamagnetic, it implies that:

    • AThe complex has unpaired electrons.
    • BThe splitting energy is zero.
    • CThe complex is paramagnetic.
    • DAll electrons are paired.
    Show answer & explanation

    Correct answer: D — All electrons are paired.

    Diamagnetism occurs when all electrons in the complex are paired, meaning there are no net unpaired electrons.

  8. Q8. Which of the following transition metals exhibits the highest preference for forming complex ions with the coordination number 6?

    • ARhodium (Rh)
    • BNickel (Ni)
    • CCobalt (Co)
    • DIron (Fe)
    Show answer & explanation

    Correct answer: C — Cobalt (Co)

    Cobalt (Co) and Iron (Fe) are common transition metals that readily form octahedral complexes (coordination number 6). While the specific preference depends on the ligand, Co(III) and Fe(III) complexes are well-known examples of octahedral coordination.

  9. Q9. Which statement best describes the general tendency of transition metals to form covalent bonds?

    • AThey form a mixture of ionic and covalent bonds
    • BThey predominantly form ionic bonds
    • CThey primarily form covalent bonds
    • DThey exclusively form ionic bonds
    Show answer & explanation

    Correct answer: A — They form a mixture of ionic and covalent bonds

    Transition metals exhibit variable bonding character; they form ionic bonds when bonding with highly electronegative elements and covalent bonds when bonding with less electronegative elements, leading to a mixture of both.

  10. Q10. Which type of isomerism is exhibited by coordination compounds involving polydentate ligands?

    • AGeometric isomerism
    • BChain isomerism
    • CIonization isomerism
    • DLinkage isomerism
    Show answer & explanation

    Correct answer: D — Linkage isomerism

    Linkage isomerism occurs when the connectivity of the ligands changes, leading to different spatial arrangements of the same set of ligands, which is common in polydentate complex formation.

  11. Q11. In coordination compounds, the coordination number of a central metal ion is defined by:

    • Athe oxidation state of the metal
    • Bthe total number of electrons
    • Cthe total number of ligands attached
    • Dthe number of unpaired electrons
    Show answer & explanation

    Correct answer: C — the total number of ligands attached

    The coordination number is the number of ligand donor atoms directly bonded to the central metal ion.

  12. Q12. Which type of complex ion is typically expected to be high spin based on the crystal field theory in an octahedral geometry?

    • Ad⁶
    • Bd⁵
    • Cd¹⁰
    • Dd¹
    Show answer & explanation

    Correct answer: B — d⁵

    For d⁵ configuration (e.g., Mn²⁺), the pairing energy is relatively high compared to the crystal field splitting energy (Δₒ), resulting in the maximum number of unpaired electrons, thus favoring the high spin state. (d¹ is always low spin, d⁶ can be high or low spin depending on ligands, d¹⁰ is always low spin).

  13. Q13. The general electronic configuration of the elements in the d-block is characterized by the involvement of which type of orbitals in the valence shell?

    • Af orbitals
    • Bd orbitals
    • Cs orbitals
    • Dp orbitals
    Show answer & explanation

    Correct answer: B — d orbitals

    Transition elements (d-block) are defined by the fact that the last electron enters the d-orbital, meaning they possess partially filled d-orbitals in their valence shell.

  14. Q14. The elements of the f-block are primarily characterized by:

    • AVariable oxidation states
    • BIncomplete d-orbital filling
    • CLanthanide contraction
    • DFormation of colored ions
    Show answer & explanation

    Correct answer: C — Lanthanide contraction

    The f-block elements (lanthanides and actinides) are characterized by the filling of the 4f and 5f orbitals, which leads to the unique properties associated with the lanthanide contraction.

  15. Q15. The magnetic moment of a transition metal ion is directly proportional to:

    • AThe crystal field splitting energy
    • BThe number of unpaired electrons
    • CThe coordination number
    • DThe total number of electrons
    Show answer & explanation

    Correct answer: B — The number of unpaired electrons

    The magnetic moment (spin-only) is directly proportional to the number of unpaired electrons. The formula used is μ= √(n(n+2)) BM, where n is the number of unpaired electrons.

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