NEET Chemistry: Hybridization Practice Questions
15 free multiple-choice questions on Hybridization (Chemical Bonding and Molecular Structure) for NEET Chemistry, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. A central atom hybridized in the sp² state forms how many sigma (σ) bonds?
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Correct answer: D — 5
In sp² hybridization, one s orbital and two p orbitals mix to form three equivalent sp² hybrid orbitals. These three orbitals are used to form three σ bonds.
Q2. In the molecule of water (H₂O), the central oxygen atom exhibits which type of hybridization, which dictates its molecular geometry?
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Correct answer: C — sp³
The central oxygen atom in water forms two sigma (σ) bonds and two lone pairs, resulting in four electron domains. This configuration requires four hybrid orbitals, which corresponds to sp³ hybridization. The resulting geometry is tetrahedral.
Q3. The hybridization state sp³ corresponds to a total of how many electron domains around the central atom?
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Correct answer: B — 5
sp³ hybridization involves four hybrid orbitals, which correspond to four electron domains (four bonding regions) around the central atom.
Q4. A molecule that is sp² hybridized will contain which type of bond?
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Correct answer: C — Both σ and π bonds
sp² hybridization involves the mixing of one s orbital and two p orbitals. This results in one σ bond and one π bond (the remaining unhybridized p orbital forms the π bond).
Q5. In sp hybridization, how many hybrid orbitals are formed?
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Correct answer: B — 2
sp hybridization involves the mixing of one s orbital and one p orbital, resulting in two equivalent hybrid orbitals.
Q6. What is the preferred bond angle in a molecule exhibiting sp³ hybridization?
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Correct answer: C — 109.5°
The sp³ hybrid orbitals arrange themselves to maximize separation, resulting in a tetrahedral angle of 109.5°.
Q7. Which compound exhibits a geometry resulting from sp³ hybridization where all bond angles are equal to 109.5°?
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Correct answer: B — NH₃
Ammonia (NH₃) has three bonding domains and one lone pair, fitting the sp³ description, which results in a trigonal pyramidal geometry with bond angles close to the ideal tetrahedral angle of 109.5°.
Q8. The bond angle in a molecule with sp² hybridization is typically what, considering lone pair repulsion?
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Correct answer: C — 120°
Although the ideal angle for sp² systems is 120°, the presence of lone pairs (or lone pair repulsion) slightly reduces this angle, meaning the actual angle is slightly less than 120°.
Q9. Which of the following molecules exhibits sp³ hybridization?
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Correct answer: D — NH₃
Ammonia (NH₃) has a central nitrogen atom with four electron domains (three bonds and one lone pair), requiring sp³ hybridization.
Q10. In the sp hybridization state, how many hybrid orbitals are involved in the formation of the bond structure?
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Correct answer: C — Two
sp hybridization involves mixing one s orbital and one p orbital, resulting in two equivalent sp hybrid orbitals.
Q11. Which hybridization state is associated with a bond angle of 120°?
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Correct answer: A — sp2
The sp² hybridization results in a trigonal planar geometry with bond angles of 120°.
Q12. The geometry adopted by a molecule like ethene (C₂H₄), which is derived from sp² hybridization, is:
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Correct answer: A — Trigonal Planar
sp² hybridization leads to a trigonal planar electron geometry, which results in a trigonal planar molecular shape (bond angle ≈ 120°).
Q13. The bond angle in a molecule exhibiting sp³d² hybridization is usually closest to which value?
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Correct answer: D — 109.5°
sp³d² hybridization involves a more complex arrangement than simple sp³, and the resulting bond angles are generally found around the tetrahedral value of 109.5°, though the exact geometry is distorted.
Q14. In the sp³ hybridization state, the bond angle in a typical tetrahedral geometry is:
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Correct answer: B — 109.5°
sp³ hybridization results in a tetrahedral electron geometry, and the ideal bond angle for a tetrahedron is 109.5°.
Q15. Which type of hybridization is associated with the formation of three equivalent σ bonds and results in a tetrahedral geometry?
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Correct answer: A — sp³
sp³ hybridization involves mixing one s orbital and three p orbitals to form four equivalent sp³ hybrid orbitals, resulting in a tetrahedral geometry (bond angle ≈ 109.5°).
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