Free daily NEET & JEE PYQs, quizzes & mock tests on TelegramJoin free →

NEET Physics: The first law of thermodynamics Practice Questions

15 free multiple-choice questions on The first law of thermodynamics (Thermodynamics) for NEET Physics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.

Practice thousands more NEET questions in the app →
  1. Q1. Which term in the First Law of Thermodynamics represents energy transferred across the boundary of a system?

    • APressure
    • BWork
    • CInternal Energy
    • DHeat
    Show answer & explanation

    Correct answer: D — Heat

    Heat (Q) is the transfer of thermal energy across the boundary of a system. Work (W) is the transfer of energy via mechanical means. Internal Energy (ΔU) is the total energy stored within the system.

  2. Q2. Which of the following represents the relationship described by the First Law of Thermodynamics?

    • ATemperature is directly proportional to internal energy.
    • BWork is always negative during an isothermal process.
    • CEnergy can neither be created nor destroyed.
    • DHeat is a vector quantity.
    Show answer & explanation

    Correct answer: C — Energy can neither be created nor destroyed.

    The First Law of Thermodynamics is fundamentally a statement of the conservation of energy, which implies that energy cannot be created or destroyed, only transformed.

  3. Q3. In a process where no heat is exchanged with the surroundings, the change in internal energy of the system is determined solely by the work done. This type of process is known as:

    • AAdiabatic process
    • BIsobaric process
    • CIsothermal process
    • DIsochoric process
    Show answer & explanation

    Correct answer: A — Adiabatic process

    If no heat is exchanged (Q=0), the process is adiabatic. In an adiabatic process, ΔU = -W.

  4. Q4. Which of the following statements represents the First Law of Thermodynamics?

    • AEnergy can neither be created nor destroyed, only transformed.
    • BThe entropy of an isolated system always increases.
    • CEnergy can be created or destroyed.
    • DHeat flows spontaneously from hot to cold bodies.
    Show answer & explanation

    Correct answer: A — Energy can neither be created nor destroyed, only transformed.

    The First Law of Thermodynamics is based on the principle of energy conservation, stating that energy cannot be created or destroyed, only changed in form.

  5. Q5. If a process occurs at constant volume, the change in internal energy of the system is related to the heat flow by which equation?

    • AΔU = Q - W
    • BΔU = Q
    • CΔU = 0
    • DΔU = Q + W
    Show answer & explanation

    Correct answer: A — ΔU = Q - W

    For a constant volume process, the work done (W) is zero because ΔV = 0 for volume change. Therefore, ΔU = Q - 0, which simplifies to ΔU = Q.

  6. Q6. If a system absorbs heat and performs work on its surroundings, the change in the system's internal energy will be:

    • AEqual to zero, assuming an adiabatic process.
    • BIncreased by the total heat absorbed.
    • CDecreased by the work done.
    • DIncreased by the net result of heat input and work output.
    Show answer & explanation

    Correct answer: D — Increased by the net result of heat input and work output.

    According to the First Law (ΔU = Q - W), if heat is supplied (Q>0) and work is done by the system (W>0), the change in internal energy is the difference, which accounts for both energy input and energy output.

  7. Q7. In the thermodynamic expression ΔU = Q - W, what does ΔU represent?

    • AHeat absorbed by the system.
    • BChange in internal energy of the system.
    • CChange in heat flow across the boundary.
    • DWork done by the system.
    Show answer & explanation

    Correct answer: B — Change in internal energy of the system.

    ΔU represents the change in the internal energy of the system.

  8. Q8. If a system absorbs 500 J of heat and performs 200 J of work on its surroundings, what is the change in internal energy of the system?

    • A700 J
    • B-700 J
    • C300 J
    • D-300 J
    Show answer & explanation

    Correct answer: C — 300 J

    Using the First Law: ΔU = Q - W. Here, Q = +500 J (absorbed) and W = +200 J (work done by the system). ΔU = 500 J - 200 J = 300 J.

  9. Q9. If a system absorbs 500 Joules of heat and performs 150 Joules of work on its surroundings, what is the change in the internal energy of the system?

    • A650 J
    • B500 J
    • C-150 J
    • D350 J
    Show answer & explanation

    Correct answer: D — 350 J

    Using the First Law, ΔU = Q - W. Here, Q = +500 J (absorbed) and W = +150 J (done by the system). Therefore, ΔU = 500 - 150 = 350 J.

  10. Q10. According to the First Law of Thermodynamics, the change in internal energy of a system is equal to the heat supplied to the system minus the work done by the system. Which of the following statements correctly represents this relationship?

    • AΔU = Q + W
    • BΔU = Q / W
    • CQ = ΔU + W
    • DΔU = Q - W
    Show answer & explanation

    Correct answer: D — ΔU = Q - W

    The First Law of Thermodynamics is mathematically expressed as ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat absorbed by the system, and W is the work done by the system.

  11. Q11. If a system absorbs heat (Q) and performs work (W) on its surroundings, the change in internal energy (ΔU) will be:

    • ADepends on the process.
    • BZero.
    • CNegative.
    • DPositive.
    Show answer & explanation

    Correct answer: C — Negative.

    According to the First Law (ΔU = Q - W), if heat is absorbed (Q>0) and work is done by the system (W>0), the change in internal energy will be less than the heat absorbed. If work is done *by* the system, ΔU decreases (or Q-W results in a smaller net change). In this context, if Q is heat *added* to the system and W is work *done* *by* the system, ΔU is Q-W. For simple conceptual understanding, the change in energy depends on the net flow. If work is done *by* the system, internal energy decreases unless heat is also added. A simpler view: Heat added results in an increase in internal energy, adjusted by work done.

  12. Q12. In a thermodynamic process, if 500 Joules of heat is supplied to a system, and the system performs 200 Joules of work on its surroundings, what is the change in the internal energy of the system?

    • A300 J
    • B100 J
    • C200 J
    • D500 J
    Show answer & explanation

    Correct answer: A — 300 J

    According to the First Law of Thermodynamics, the change in internal energy (ΔU) is equal to the heat supplied to the system (Q) minus the work done by the system (W): ΔU = Q - W. Here, Q = 500 J and W = 200 J. Therefore, ΔU = 500 J - 200 J = 300 J.

  13. Q13. The internal energy (U) of a system is a state function. This means that the change in internal energy depends only on:

    • AThe external pressure applied.
    • BThe rate of heat transfer involved.
    • CThe initial and final states of the system.
    • DThe path taken by the system.
    Show answer & explanation

    Correct answer: C — The initial and final states of the system.

    A state function (like internal energy) depends only on the initial and final states of the system, not on the path taken between those states.

  14. Q14. The work done by a gas during an expansion is typically considered to be:

    • APositive (work done by the gas).
    • BNegative (work done on the gas).
    • CZero.
    • DDependent on the heat loss.
    Show answer & explanation

    Correct answer: A — Positive (work done by the gas).

    When a gas expands, it performs work on its surroundings, meaning the system itself does work, hence the work done *by* the system is positive.

  15. Q15. If a process involves no heat exchange (Q=0) and no work done (W=0), what is the resulting change in the internal energy (ΔU)?

    • AΔU > 0
    • BΔU is undefined
    • CΔU = -W
    • DΔU = 0
    Show answer & explanation

    Correct answer: D — ΔU = 0

    According to the First Law (ΔU = Q - W), if both Q and W are zero, then ΔU = 0 - 0 = 0. This signifies that the internal energy remains unchanged.

Keep going — practice on Padhai Karlo

Padhai Karlo gives you unlimited NEET practice: chapter-wise questions, timed quizzes, and full mock tests with an All-India Rank — free to start.

Get the free Android app →