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NEET Physics: dimensional analysis Practice Questions

13 free multiple-choice questions on dimensional analysis (Physics and Measurement) for NEET Physics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.

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  1. Q1. The principle of homogeneity of dimensions is applied when:

    • AChecking the dimensional correctness of an equation
    • BPerforming multiplication of physical quantities
    • CAdding physical quantities
    • DCalculating the unit of a derived quantity
    Show answer & explanation

    Correct answer: A — Checking the dimensional correctness of an equation

    The principle of homogeneity states that in an equation, the dimensions of all terms on both sides must be the same. This is used to check dimensional consistency.

  2. Q2. The dimensions of the physical quantity work (energy) are:

    • AM L² T⁻²
    • BM L T
    • CL² T⁻²
    • DM L T⁻¹
    Show answer & explanation

    Correct answer: A — M L² T⁻²

    Work (Energy) is defined as Force times distance (W = Fd). Since Force (F=ma) has dimensions MLT⁻² and distance (L) has dimension L, the dimensions of work are (MLT⁻²) × L = ML²T⁻².

  3. Q3. The dimensional formula for density is [M L⁻³]. If we express density in terms of fundamental dimensions, which dimensions are involved?

    • A[M L⁻³]
    • B[M L T⁻¹]
    • C[M² L⁻³]
    • D[M³ L⁻³]
    Show answer & explanation

    Correct answer: A — [M L⁻³]

    The dimensional formula for density is mass divided by volume (ρ= m/V). The dimensions are [M] / [L³] = [M L⁻³].

  4. Q4. The dimensions of momentum are the same as the dimensions of:

    • AMass times velocity
    • BPressure
    • CEnergy per unit time
    • DForce
    Show answer & explanation

    Correct answer: A — Mass times velocity

    Momentum (p) is defined as mass times velocity (p = mv). Its dimensions are [MLT⁻¹]. Option B, Mass times velocity, directly corresponds to the definition of momentum and thus has the same dimensions.

  5. Q5. The dimensional formula for velocity is [LT⁻¹]. If we analyze the dimensions of acceleration, which is [LT⁻²], this relationship confirms the dimensional consistency of the formula.

    • AIncorrect, acceleration must have dimensions of [L/T].
    • BIncorrect, time must be raised to the power of 1 in the ratio.
    • CCorrect, because L/T² matches the required dimensions.
    • DCorrect, because (LT⁻¹)/(T⁻²) = L/T.
    Show answer & explanation

    Correct answer: C — Correct, because L/T² matches the required dimensions.

    Acceleration is defined as change in velocity over time (Velocity/Time), thus its dimensions are [LT⁻¹] / [T] = [LT⁻²]. This confirms dimensional consistency.

  6. Q6. The dimension of magnetic flux density (B) is the same as the dimension of:

    • AMagnetic field intensity (I)
    • BMagnetic field strength (B)
    • CMagnetic field energy density
    • DMagnetic field (H)
    Show answer & explanation

    Correct answer: D — Magnetic field (H)

    Magnetic flux density (B) is often used interchangeably with Magnetic field strength (H) in some contexts or derived from B⃗ = μH⃗. However, dimensionally, Magnetic Flux Density (B) is equivalent to Magnetic Field Strength (H) in terms of [M T⁻² I⁻¹] or [M L T⁻² I⁻¹], which is dimensionally equivalent to the magnetic field intensity (H) in SI units, making A the most conceptually linked dimensionally. (Note: In strict SI dimensional analysis, B and H are often treated as having the same dimensions when considering the field relationship.)

  7. Q7. If the dimensional formula for a physical quantity is [M¹L²T⁻²], what is the physical quantity represented by this formula?

    • AEnergy
    • BForce
    • CVelocity
    • DAcceleration
    Show answer & explanation

    Correct answer: A — Energy

    The dimensions [M¹L²T⁻²] correspond to the dimensions of Force (or Work/Energy, which have the same dimensions). Force is MLT⁻².

  8. Q8. The dimensional formula for force is [M L T⁻²]. Which of the following is the dimension of momentum?

    • A[M L² T⁻¹]
    • B[M L² T⁻²]
    • C[M L T⁻¹]
    • D[M L⁻¹ T⁻²]
    Show answer & explanation

    Correct answer: C — [M L T⁻¹]

    Momentum (p) is defined as mass times velocity (p = mv). The dimensions are [M] × [L T⁻¹], which gives [M L T⁻¹].

  9. Q9. Which of the following combinations has the dimensions of angular momentum?

    • AML²T⁻¹
    • BMLT⁻¹
    • CMLT
    • DM L T⁻²
    Show answer & explanation

    Correct answer: A — ML²T⁻¹

    Angular momentum (L) is defined as the product of the moment of inertia (I, dimension ML²) and angular velocity (ω, dimension T⁻¹). Therefore, the dimension is (ML²) × (T⁻¹) = ML²T⁻¹.

  10. Q10. The dimensional formula for force is:

    • AML²T⁻²
    • BMLT⁻²
    • CMLT⁻¹
    • DM¹L¹T⁻²
    Show answer & explanation

    Correct answer: A — ML²T⁻²

    Force (F) is defined as mass (M) times acceleration (L/T²). Therefore, the dimensions are M * (L/T²) = MLT⁻².

  11. Q11. The unit of energy in the SI system is Joule (J). The dimensional formula for energy is:

    • A[M L T⁻²]
    • B[M L² T⁻¹]
    • C[M L T⁻¹]
    • D[M L² T⁻²]
    Show answer & explanation

    Correct answer: D — [M L² T⁻²]

    Energy (Work) is defined as Force times Distance (W = F · d). Since Force is M L T⁻² and Distance is L, the dimension of Energy is (M L T⁻²) × L = [M L² T⁻²]. This corresponds to Option C.

  12. Q12. What are the fundamental dimensions of mass, length, and time?

    • AT M L
    • BL T M
    • CM L² T
    • DM L T
    Show answer & explanation

    Correct answer: D — M L T

    The fundamental dimensions of any physical quantity are Mass (M), Length (L), and Time (T). Thus, the dimensions of mass are M, length are L, and time are T.

  13. Q13. The dimensional formula for density (ρ= m/V) is:

    • AML²T⁻²
    • BMLT⁻²
    • CML⁻¹T⁻²
    • DMLT⁻¹
    Show answer & explanation

    Correct answer: C — ML⁻¹T⁻²

    Density is mass divided by volume. The dimensions are [M] / [L³] = ML⁻³T⁻².

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