NEET Chemistry: Alkenes geometrical isomerism and addition reactions Practice Questions
15 free multiple-choice questions on Alkenes geometrical isomerism and addition reactions (Hydrocarbons) for NEET Chemistry, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.
Practice thousands more NEET questions in the app →Q1. Which of the following isomers of propene can exhibit geometrical isomerism?
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Correct answer: C — 2-Butene
Geometrical isomerism occurs in alkenes where each carbon of the double bond is attached to two different groups. 2-Butene (CH₃CH=CHCH₃) has two different groups on each carbon (methyl and ethyl groups), allowing for cis/trans isomerism. Propene and Propane do not have this structural arrangement to exhibit geometrical isomerism.
Q2. Which of the following structural features is necessary for an alkene to exhibit geometrical isomerism?
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Correct answer: B — Presence of a C=C bond
Geometrical isomerism (cis-trans isomerism) requires restricted rotation around the double bond, which is characteristic of the C=C bond. The presence of two different groups on each carbon of the double bond is also required, but the C=C bond itself is the foundation of the isomerism possibility.
Q3. If an alkene has the general formula RCH=CH₂ where R is an alkyl group, what type of isomerism can be observed if R is an unsymmetrical group?
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Correct answer: D — Optical and geometrical isomerism
If R is an unsymmetrical group, the alkene can exhibit both geometrical isomerism (if R is not H) and optical isomerism (if the molecule lacks a plane of symmetry).
Q4. Which isomer of 2-methylbut-2-ene exhibits a specific geometric relationship between its substituents?
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Correct answer: B — trans-2-methylbut-2-ene
2-methylbut-2-ene is an asymmetrical alkene that can exist as cis or trans isomers, demonstrating geometrical isomerism.
Q5. According to Markovnikov's rule, the addition of HBr to propene (CH₃CH=CH₂) results in the formation of:
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Correct answer: D — 2-Bromopropane
Markovnikov's rule states that the hydrogen atom adds to the carbon with more hydrogen atoms. In the addition of HBr to propene, the bromine adds to the more substituted carbon, yielding 2-Bromopropane.
Q6. The addition of hydrogen across the double bond of an alkene is known as:
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Correct answer: D — Hydrogenation
The reaction where hydrogen (H₂) is added across a multiple bond (alkene) to form a single bond (alkane) is specifically called hydrogenation.
Q7. The addition of hydrogen bromide (HBr) to an alkene generally follows which rule?
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Correct answer: A — Markovnikov's rule
The addition of HX (like HBr) to unsymmetrical alkenes follows Markovnikov's rule, where the hydrogen atom adds to the carbon with more hydrogen atoms, resulting in the formation of the more stable carbocation intermediate.
Q8. The formula for the isomer where the two substituents on the double bond are on the same side (cis isomer) is characteristic of which type of isomerism?
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Correct answer: D — Geometrical isomerism
The arrangement of substituents on a double bond, leading to different spatial orientations (cis or trans), is defined as geometrical isomerism. Cis specifically refers to the configuration where the higher priority groups are on the same side of the double bond.
Q9. The addition of water (H₂O) to an alkene typically results in the formation of which type of product?
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Correct answer: B — Alcohols
Alkenes react with water in the presence of a catalyst (acid) via acid-catalyzed hydration, which leads to the formation of alcohols. This reaction is known as hydration.
Q10. Which of the following pairs of alkenes exhibits geometric isomerism (cis-trans isomerism)?
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Correct answer: A — But-2-ene
Geometric isomerism (cis-trans isomerism) occurs in alkenes where restricted rotation is possible around the π-bond, which happens when both carbon atoms of the double bond are attached to two different groups. But-2-ene (CH₃CH=CHCH₃) has two different groups attached to each carbon, allowing for cis and trans isomers. Propene (CH₃CH=CH₂) does not have geometric isomers.
Q11. Which structural feature is necessary for an alkene to exhibit geometrical isomerism?
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Correct answer: C — presence of a double bond
Geometrical isomerism (cis-trans isomerism) occurs when restricted rotation around a carbon-carbon double bond is possible, and the groups attached to each carbon are different, allowing for different spatial arrangements.
Q12. Which of the following correctly describes the geometric isomerism found in alkenes?
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Correct answer: A — Isomerism due to restricted rotation about the π-bond
Geometric isomerism (cis-trans isomerism) in alkenes arises because rotation about the π-bond is restricted, leading to distinct spatial arrangements of substituents on the double bond.
Q13. Which of the following compounds exhibits cis-trans isomerism?
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Correct answer: D — 2-Butene
2-Butene (CH₃CH=CHCH₃) has restricted rotation, allowing for cis and trans geometric isomers. Propene (CH₃CH=CH₂) does not exhibit this isomerism.
Q14. Which of the following pair represents the geometric isomers of 2-butene?
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Correct answer: C — cis-2-butene and trans-2-butene
2-butene (CH₃CH=CHCH₃) has two different geometric isomers: cis-2-butene (where the higher priority groups are on the same side) and trans-2-butene (where they are on opposite sides).
Q15. In the addition reaction of an unsymmetrical alkene with hydrogen halide, which principle governs the placement of the hydrogen atom?
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Correct answer: A — Markovnikov's rule
Markovnikov's rule states that in the addition of H-X across a double bond, the hydrogen atom adds to the carbon atom that already has more hydrogen atoms.
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