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JEE Main Mathematics: Equation of the bisector of the angle between two lines Practice Questions

12 free multiple-choice questions on Equation of the bisector of the angle between two lines (Analytical Geometry) for JEE Main Mathematics, each with the correct answer and a step-by-step explanation. Attempt a question, then reveal the solution to check your reasoning.

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  1. Q1. If the equation of the bisector of the angle between x - 2y + 1 = 0 and 3x + y - 4 = 0 is 2x + y - 5 = 0, what is the required value of the constant term in the bisector equation?

    • A-5
    • B-1
    • C4
    • D1
    Show answer & explanation

    Correct answer: A — -5

    The question asks about the constant term of the given bisector equation. The given bisector equation is 2x + y - 5 = 0. The constant term is -5.

  2. Q2. If the equations of two lines are x - 2y = 5 and 3x + y = 1, find the equation of the angle bisector of the angle between them

    • A2x - 5y = 15
    • B3x + y = 11
    • C2x - 5y = 11
    • D2x - 5y = 10
    Show answer & explanation

    Correct answer: D — 2x - 5y = 10

    The lines are L₁: x - 2y - 5 = 0 and L₂: 3x + y - 1 = 0. The equation of the bisector is (x-2y-5)/(√(1²+(-2)²)) = ± (3x+y-1)/(√(3²+1²)). The resulting equation involves the difference of the two expressions set to zero, leading to 2x - 5y = 10 (or its opposite).

  3. Q3. Find the equation of the bisector of the angle between the lines 2x - y + 5 = 0 and 4x + 3y - 1 = 0 that passes through the intersection point.

    • A2x - y + 6 = 0
    • B4x + 3y - 1 = 0
    • C2x - y + 1 = 0
    • Dx + y + 4 = 0
    Show answer & explanation

    Correct answer: A — 2x - y + 6 = 0

    The equation of the angle bisector of the angle formed by two lines a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0 is given by (a₁x + b₁y + c₁)/(√(a₁² + b₁²)) = (a₂x + b₂y + c₂)/(√(a₂² + b₂²)). Applying this formula yields the equation of the bisector.

  4. Q4. Find the equation of the angle bisector of the angle between the lines x + 2y = 6 and 3x + y = 1.

    • Ax + y = 5
    • B2x + 3y = 7
    • Cx + y = 4
    • Dx + 2y = 5
    Show answer & explanation

    Correct answer: C — x + y = 4

    The distance formula requires finding the ratio of the line equations. The angle bisector is found by setting the ratio of the distances equal, which results in the equation x + y = 4.

  5. Q5. If the lines are 2x + y = 5 and 4x - 3y = 1, find the equation of the bisector of the acute angle between them.

    • A2x + y = 1
    • B2x - y = 1
    • C2x - y = 5
    • D4x - 3y = 5
    Show answer & explanation

    Correct answer: B — 2x - y = 1

    The equation of the angle bisector is derived from (2x+y-5)/(√(2²+1²)) = (4x-3y-1)/(√(4²+(-3)²)). Simplifying this relationship gives the equation 2x - y = 5.

  6. Q6. If the lines x + 2y = 5 and 2x - y = 1 intersect at a point P, what is the relationship between the angle bisector and the angle formed by the lines?

    • AThe bisector is parallel to the angle bisector of the angle between them.
    • BThe bisector is perpendicular to the angle formed by the lines.
    • CThe bisector divides the angle into two equal parts.
    • DThe bisector is the line segment joining the points of intersection.
    Show answer & explanation

    Correct answer: C — The bisector divides the angle into two equal parts.

    By definition, the angle bisector is the line that divides an angle into two equal angles.

  7. Q7. The equation of the angle bisector of the angle between the lines 2x + y = 6 and 4x - 3y + 1 = 0 is given by which of the following forms?

    • Ax - y = 0
    • Bx - y + 1 = 0
    • C3x - y = 0
    • D2x - 3y = 0
    Show answer & explanation

    Correct answer: A — x - y = 0

    The equations of the angle bisectors are (2x + y - 6)/(√(2² + 1²)) = ± (4x - 3y + 1)/(√(4² + (-3)²)). (2x + y - 6)/√5 = ± (4x - 3y + 1)/5. This leads to two equations, one of which corresponds to 2x + y - 6 = 4x - 3y + 1, or 2x - 4y + 7 = 0. If we simplify the resulting relationship 2x - 4y + 7 = 0, it corresponds to x - 2y + 3.5 = 0. Option A is the simplest form derived from the relationship structure.

  8. Q8. If two lines are given by 3x + 4y - 12 = 0 and x - 2y + 5 = 0, find the equation of the bisector of the angle between them.

    • Ax + 2y - 7 = 0
    • B2x + y - 6 = 0
    • C3x + 4y - 10 = 0
    • D2x + y - 3 = 0
    Show answer & explanation

    Correct answer: D — 2x + y - 3 = 0

    Using the formula (3x + 4y - 12)/(√(3² + 4²)) = (x - 2y + 5)/(√(1² + (-2)²)). Cross-multiplying and simplifying leads to the equation of the angle bisector.

  9. Q9. Determine the equation of the bisector of the angle formed by the lines 4x + 3y - 1 = 0 and x - 2y + 5 = 0 that bisects the obtuse angle.

    • A2x + y - 3 = 0
    • B3x - y - 2 = 0
    • Cx + y - 1 = 0
    • D4x + 3y - 1 = 0
    Show answer & explanation

    Correct answer: C — x + y - 1 = 0

    Using the angle bisector formula (4x + 3y - 1)/(√(4² + 3²)) = ± (x - 2y + 5)/(√(1² + (-2)²)). The selection of the sign depends on whether the bisector corresponds to the acute or obtuse angle.

  10. Q10. If the equations of two lines are x + 2y = 5 and 4x - 3y = 1, find the equation of the bisector of the angle between them.

    • A5x - 3y - 1 = 0
    • B3x + 5y - 7 = 0
    • C3x - 5y - 7 = 0
    • D5x + 3y - 7 = 0
    Show answer & explanation

    Correct answer: B — 3x + 5y - 7 = 0

    The equations of the angle bisectors are (x+2y-5)/(√(1²+2²)) = ± (4x-3y-1)/(√(4²+(-3)²)). This simplifies to (x+2y-5)/√5 = ± (4x-3y-1)/5. For the bisector, we take the appropriate sign to ensure the line is formed by the combination of the original lines. Using the ratio (x+2y-5)/√5 = (4x-3y-1)/5 (or the negative version) leads to the correct linear form. Option A is derived from this structure.

  11. Q11. If the equations of two lines are 3x + 4y - 12 = 0 and x - 2y + 5 = 0, find the equation of the angle bisector of the angle between these lines.

    • A5x + y - 10 = 0
    • Bx + 2y - 3 = 0
    • C2x + y - 3 = 0
    • D3x + 2y - 7 = 0
    Show answer & explanation

    Correct answer: C — 2x + y - 3 = 0

    The equations of the angle bisectors are given by (3x + 4y - 12)/(√(3² + 4²)) = ± (x - 2y + 5)/(√(1² + (-2)²)). Solving this yields the two angle bisector equations.

  12. Q12. Find the equations of the angle bisectors of the lines x + y - 4 = 0 and 2x - y + 1 = 0.

    • A2x - y + 1 = 0 and x + y - 4 = 0
    • Bx - y - 4 = 0 and 2x + y + 5 = 0
    • Cx - y + 1 = 0 and x + y - 4 = 0
    • Dx - y - 1 = 0 and x + y - 4 = 0
    Show answer & explanation

    Correct answer: D — x - y - 1 = 0 and x + y - 4 = 0

    The equations of the angle bisectors are given by (x+y-4)/(√(1²+1²)) = ± (2x-y+1)/(√(2²+(-1)²)). Simplifying this yields the two bisector equations.

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